0=y^2-10y+26

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Solution for 0=y^2-10y+26 equation: 



0=y^2-10y+26

We move all terms to the left:

0-(y^2-10y+26)=0

We add all the numbers together, and all the variables

-(y^2-10y+26)=0

We get rid of parentheses

-y^2+10y-26=0

We add all the numbers together, and all the variables

-1y^2+10y-26=0

a = -1; b = 10; c = -26;
Δ = b2-4ac
Δ = 102-4·(-1)·(-26)
Δ = -4
Delta is less than zero, so there is no solution for the equation

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